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Find the real values of x and y for which ((x-1)/(3+i)+(y-1)/(3-i))=i.
SOLUTION: Graph y=(1/3)^x. Identify the domain, asymptote, and range. Did I do this right? x=3 -2 -1 0 1 2 3 y=27 9 3 1 1/3 1/9 1/27 Domain=all real #s asymptote=y=
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Find the real values of x and y for which ((x-1)/(3+i)+(y-1)/(3-i))=i.
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If | x | < 1 and | y | < 1, then the sum of infinity of the series (x + y) + (x^2 + xy + y^2) + (x^3 + x^2y + xy^2 + y^3) + ..... to ∞ is
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